1019 : New Tortoise and the Hare

时间限制Time Limit 1 Sec 内存限制Memory Limit 128 MB 提交次数Submitted 6 Times 通过次数Solved 4 Times 标准评测Standard Judge

题目描述Description

The tortoise and the hare agreed to race again. The hare intends to let the tortoise run for a while, and then catch up with it before the finish line.

Lvtvhp respectively represent the length of the track, the speed of the tortoise (per second), the speed of the hare (per second), and the distance the tortoise has traveled when the hare starts.

Can the hare catch up with the tortoise?

输入格式Input

There are multiple test cases. Each line contains four integers Lvtvhp correspondingly.

10 <= L <= 1000, 1 <= vt < vh <= 1000, 1 <= p <= L.

The cases ends with EOF.

输出格式Output

Output a number a line corresponding to each case.

If the hare can catch up with the tortoise before (include) the finish line, the output is the time the hare need to catch up with the tortoise. The result should be accurated to two decimal places.

Otherwise, output -1.

样例Sample

提示Hint

EOF means the end of the file. In C language, we could use:

while(scanf("%d%d%d%d", &L, &vt, &vh, &p) != EOF)
{
    // Do what you need.
}

to recognise it.

出题Author

CSGrandeur

来源Source

HNCPC2024 Warmup