1021 : The Area of a Sector

时间限制Time Limit 1 秒Sec 内存限制Memory Limit 128 兆MB 提交次数Submitted 1 次Times 通过次数Solved 1 次Times

特判评测 Special

读写方式与标准评测相同。答案可能不唯一，是否正确由本题的特判程序判定，输出格式以题面为准。 I/O is the same as standard judge. Several outputs may be valid; this problem’s special judge decides correctness. Follow the output format in the statement.

输入Input	标准输入。Standard input.
输出Output	标准输出，格式以题面为准。Standard output; format as specified in the statement.

模板Template

C++ C Java Python

#include <iostream>
using namespace std;
int main() {
    int a, b;
    cin >> a >> b;
    cout << (a + b) << endl;
    return 0;
}

#include <stdio.h>
int main() {
    int a, b;
    scanf("%d%d", &a, &b);
    printf("%d\n", a + b);
    return 0;
}

import java.util.Scanner;
public class Main {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int a = in.nextInt();
        int b = in.nextInt();
        System.out.println(a + b);
    }
}

a, b = map(int, input().split())
print(a + b)

题目描述Description

Given a circle and two points on it, calculate the area of the sector with its central angle no more than 180 degrees.

输入格式Input

There are multiple test cases.

Each line contains 6 float numbers denote the center of the circle xc, yc, the two points on the circle x1, y1 and x2, y2.

1 <= xc, yc, x1, y1, x2, y2 <= 10000.

输出格式Output

The area of the sector. The result should be accurated to three decimal places.

样例Sample

提示Hint

With math.h, you could define pi (3.1415926...) as const double pi = acos(-1.0);

Inverse trigonometric function could be obtained by acos, atan, asin, etc..

Be careful that angles like pi in C/C++ are in 3.1415926... type rather than 180.

You’d better use double instead of float. Load double with "%lf" but output it with "%f".

出题Author

CSGrandeur

来源Source

2021 SZTU AI Class Qualifying