1190 : Complex Maze
Time Limit: 1 Sec Memory Limit: 128 Mb Submitted: 472 Solved: 41 SpecialJudgeDescription
The obstacles of a maze consists of 1
simple polygon.
Given a starting point and an ending point, calculate the length of the shortest path between the two points.
Both the start and end points are outside the simple polygon (and not on vertices or edges). The path cannot pass through the obstacle area.
In geometry, a simple polygon is a polygon that does not intersect itself and has no holes. That is, it is a flat shape consisting of straight, non-intersecting line segments or “sides” that are joined pairwise to form a single closed path. If the sides intersect then the polygon is not simple. The qualifier “simple” is frequently omitted, with the above definition then being understood to define a polygon in general.
–Wikipedia
Input
No more than 20
test cases.
For each test case, the first line is n
, meaning the number of vertices in the simple polygon obstacle area.
The next n
lines contain each vertex coordinate x y
in counter-clockwise order.
The last two lines contain the start and end coordinates respectively.
3 ≤ n ≤ 100, all the coordinates 0 ≤ x, y ≤ 104.
Output
One line for each test case, corresponding to the shortest path length from the start point to the end point.
The error from the correct answer should not exceed 10−5.
Sample
4 4 6 0 0 4 2 8 0 0 4 8 4
8.94427191
Hint
Author
CSGrandeur